Simple Array Sum | Hackerrank Solution | Using C/C++

Given an array of integers, find the sum of its elements.

For example, if the array ar = [1, 2, 3], 1 + 2 + 3 = 6, so return 6.

Function Description

Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.

simpleArraySum has the following parameter(s):

• ar: an array of integers

Input Format

The first line contains an integer, n, denoting the size of the array.
The second line contains n space-separated integers representing the array’s elements.

Constraints

0 < n, arr[i] < 1000

Output Format

Print the sum of the array’s elements as a single integer.

Sample Input

6
1 2 3 4 10 11

Sample Output

 31

Explanation

We print the sum of the array’s elements: 1 + 2 + 3 + 4 + 10 + 11 = 3

Solution:

Code in C

#include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> #define N 1000 int main() { int x[N],n,i,t; scanf("%d",&n); for(i=0;i<n;i++) if(i==0) {scanf("%d",&x[i]);t=x[i];} else if(getchar()==' ') {scanf("%d",&x[i]);t=t+x[i];} printf("%d",t); return 0; }

 Code in C++

#include <cmath> #include <cstdio> #include <vector> #include <iostream> #include <algorithm> using namespace std; int main() { int n; cin >> n; long long sum = 0, x; while (n--) { cin >> x; sum += x; } cout << sum << endl; return 0; }