Hackerrank Electronics Shop solution | using c++

 A person wants to determine the most expensive computer keyboard and USB drive that can be purchased with a give budget. Given price lists for keyboards and USB drives and a budget, find the cost to buy them. If it is not possible to buy both items, return .

Example

The person can buy a , or a . Choose the latter as the more expensive option and return .

Function Description

Complete the getMoneySpent function in the editor below.

getMoneySpent has the following parameter(s):

• int keyboards[n]: the keyboard prices
• int drives[m]: the drive prices
• int b: the budget

Returns

• int: the maximum that can be spent, or  if it is not possible to buy both items

Input Format

The first line contains three space-separated integers , , and , the budget, the number of keyboard models and the number of USB drive models.
The second line contains  space-separated integers , the prices of each keyboard model.
The third line contains  space-separated integers , the prices of the USB drives.

Constraints

• The price of each item is in the inclusive range .

Sample Input 0

10 2 3
3 1
5 2 8

Sample Output 0

9

Explanation 0

  Buy the  keyboard and the  USB drive for a total cost of .

Solution:

Code in c++

#include<bits h="" stdc=""> using namespace std; int main(){ int s,n,m,a,res = -1,keyboard[1001],usb[1001]; cin >> s >> n >> m; for(int i = 0; i < n; i++)cin >> keyboard[i]; for(int i = 0; i < m; i++)cin >> usb[i]; for(int i = 0; i < n; i++){ for(int j = 0; j < m; j++){ if(keyboard[i]+usb[j] <= s)res = max(res,keyboard[i]+usb[j]); } } cout << res << endl; return 0; }